Identify which reactants are being oxidized (the oxidation number increases when it reacts) and which are being reduced (the oxidation number goes down). Oxidation number (also called oxidation state) is a measure of the degree of oxidation of an atom in a substance (see: Rules for assigning oxidation numbers). The total should equal when you add all oxidation numbers: Pb + (-2) = 0 ----> Pb = +2. MEDIUM. Since the ion has a -2 charge, the oxidation state of sulfur must be +6. If you consider oxidation as the loss of electrons and gain of oxidation number, and reduction as the gain of electrons and decrease in oxidation number, the oxidation states are as follows: Pb : 0 (Elementary state) H in H2SO4 : +2. Pb in PbSO4 : +2. Pb +2 S -2 + H +1 2 O -1 2 → Pb +2 S +6 O … Identify the substance oxidised, reduced, oxidising agent and reducing agent for each of the following reactions: Pb(s) + PbO 2 (s) + 2H 2 SO 4 (aq) → 2PbSO 4 (s) + 2H 2 O(l) H in H2 : 0. H2O2 + PbS --> PbSO4 + H2O. Thank me later Shaawana is waiting for your help. Add your answer and earn points. What is the oxidation number of phosphorous in the H3PO2 molecule? gsplcu gsplcu Answer: The central atom is S. Explanation: Look at the structure. Which substance is the reducing agent in the following reaction? Pb +2 S-2 + H +1 2 O-1 2 → Pb +2 S +6 O-2 4 + H +1 2 O-2 . Conversion of PbSO4 to PbS ... chemistry. I don't think that you have written the formula of the calcium compound correctly. So, SO42- can be dealt with on its own. Now, since O is always -2, the S must be +6 to make the whole compound zero. Fe2S3 + 12HNO3 → 2Fe(NO3)3 + 3S + 6NO2 + 6H2O Sum of all oxidation number =0. D. none of these. Explanation: The oxidation number of S in P b S O 4 = 6. Pb. A compound doesn't have an oxidation number, but an element in a compound does. Therefore oxidation number of Pb is +2. Nice I mean I kinda said the answer in his question It is suggested that a precipitation mechanism to form PbSO 4 occurs under some conditions prior to the solid state … The system is compared with measurements on Pb(Hg) in H 2 SO 4 and with Pb(Hg), Hg, solid Pb in HClO 4 solution. How to calculate oxidation number of Pb in PbSO4?And Explain? Oxidation number of O=-2. PbSO4 --> Pb2+ + SO4 2- (A net dissociation reaction of the salt) SO4 has an oxidation number of -2. Within the sulfate ion, each oxygen does have a -2 oxidation state. Expert Answer: Let the oxidation number of Pb=x. You are correct that oxidation is the loss of electrons and reduction is the gaining of electrons. +1 +3 0-1 +2 +1. Oxidation number of S=+6. Pb PbO2 PbSO4 H2O H2SO4. Oxidation number of Pb is +2 Asked by | 25th Mar, 2009, 06:56: PM. Answer. Within polyatomic ions, you can frequently have oxidation states that are not "normal". Therefore x+6-8=0. THat leaves, though, the oxidation state of Pb to be +2. 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